Question

Suppose a binomial event has a probability of success of 0.3 and 1250 trials are performed. what is the standard deviation of the possible outcomes? round your answer to two decimal places.
A)8.22
B) 10.61
C) 16.20
D) 12.55

Answer 1

\[\sigma=\sqrt{np(1-p)}\]
\(n\) is the sample size/number of trials, and \(p\) is the success of probability.

Answer 2

Thank you so much :)