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If sin x = .42, what is cos x?
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\[\sin ^{2}x+\cos ^{2}x=1\]
\[\cos ^{2}x=1-\sin ^{2}x\]
\[cosx=\sqrt{1-\sin^2}x\]
find the arc sin of x first or sin(-1)0.42
you get x = 24.8349
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then find the cos of that so cos 24.8349
= 0.9075
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