Question

find the antiderivative of cuberoot of x^2 + xsqrtx

Answer 1

is this your question
?
\(\Large \int \sqrt[3]{x^2 + x\sqrt x}dx\)
??

or

Answer 2

\(\Large \int \sqrt[3]{x^2} + x\sqrt xdx\)

Answer 3

yes

Answer 4

the second one

Answer 5

then its easy :)
do you know
\(\Large \int x^n dx =...?\)

Answer 6

yes

Answer 7

x^n+1/ n+1

Answer 8

good

so
\(\Large \sqrt[3]{x^2} = x^{\dfrac{2}{3}}\)
so n = 2/3

Answer 9

\(\Large x \sqrt x = x^ {1+1/2} = x^{3/2}\)
so for 2nd term n = 3/2

Answer 10

got this ?

Answer 11

yeah! thank you so much!

Answer 12

welcome ^_^
and since you're new here
\(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)

Answer 13

thanks!