Question

find the roots of y=2x^2-4x-1

Answer 1

\(\large\color{blue}{ \rm 2x^2-4x-1=y}\)
\(\large\color{blue}{ \rm 2x^2-4x-1=0}\)
\(\large\color{blue}{ \rm 2x^2-4x-1+3=0+3}\)
\(\large\color{blue}{ \rm 2x^2-4x+2=3}\)
\(\large\color{blue}{ \rm 2(x^2-2x+1)=3}\)
\(\large\color{blue}{ \rm x^2-2x+1=3/2}\)
\(\large\color{blue}{ \rm (x-1)^2=3/2}\)

Answer 2

can you finish the problem ?

Answer 3

\[x-1=\sqrt{\frac{ 3 }{ 2 }}\]

Answer 4

?

Answer 5

Yes, but you forgot \(\large\color{blue}{ \rm ± }\) (√2/√3)

Answer 6

oh, thank you!

Answer 7

this is not it.

Answer 8

\(\large\color{blue}{ \rm x-1=± (~\sqrt{3} ~ ~/~\sqrt{2} ~)}\)
\(\large\color{blue}{ \rm x=1± (~\sqrt{3} ~ ~/~\sqrt{2} ~)}\)
\(\large\color{blue}{ \rm x=1± (~\sqrt{6} ~ ~/2)}\)

Answer 9

there.