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OpenStudy (anonymous):
zepdrix (zepdrix):
|dw:1402086404698:dw|Hello Ms tiff :)
Does this diagram look correct?
zepdrix (zepdrix):
If we take the ratio of the sides of the smaller triangle,
we can `equate` them to the sides of the larger triangle since the triangles are similar
OpenStudy (anonymous):
it does look correct :)
zepdrix (zepdrix):
\[\Large\rm \frac{4}{6}=\frac{4+x}{6+2}\]Understand how I set that up? :o
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zepdrix (zepdrix):
Do you have multiple choices for this question?
OpenStudy (anonymous):
I do understand :) No, I just have to fill in a box
OpenStudy (anonymous):
so x=4/3?
zepdrix (zepdrix):
Mmmm yah that sounds about right!
OpenStudy (anonymous):
THANKYOU SO MUCH! would you PLEASE help me with another one? I truly need help
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OpenStudy (anonymous):
I need to find the measure of angle W
zepdrix (zepdrix):
|dw:1402086938406:dw|When we have an inscribed angle like this x,
it is half the measure of the length of the arc.
So in the example I made, \(\Large\rm \angle x=\frac{1}{2}\stackrel{\frown}{n}\)