Question

(x-3)(x-5)+(x-7)(x-3)-(x+7)(x-6)=0
what is x

Answer 1

expand , add like terms, and solve for x.

Answer 2

im still lost with the negitives so far i have
(x^2-8x+15)+(x^2-10x+21)-(x^2-13x-42)

Answer 3

Assuming you've done it correctly, distribute the negative for the last quad expression to get:

(x^2 - 8x + 15) + (x^2 - 10x + 21) - x^2 + 13x + 42

Then group like terms together

(x^2 + x^2 - x^2) + (13x - 8x - 10x) + (15 + 21 + 42)

Then factor out the common variable:
(1 + 1 - 1)x^2 + (13 - 8 - 10)x + (15 + 21 + 42)

Answer 4

Actually, I get the feeling your expansion of (x + 7)(x - 6) isn't 100% accurate