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OpenStudy (anonymous):
What are the zeros of 3x^4+27x^2+9
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geerky42 (geerky42):
Let \(u = x^2\), so now you have \(3x^4+27x^2+9 \Longrightarrow 3u^2+27u+9\)
geerky42 (geerky42):
Then use quadratic formula to solve for u.
geerky42 (geerky42):
Can you do that? @paris32
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