Question

Integration:

Answer 1

\[\LARGE \int~\frac{cosx}{\sqrt{4-cos^2x}}~dx\]

Answer 2

can you help me? i @ted you

Answer 3

\[\cos^2x = 1-\sin^2x\]

\[\int\limits \frac{ cosx }{ \sqrt{\sin^2x+3} }dx \]

u = sinx, du = cosxdx

\[\int\limits \frac{ 1 }{ \sqrt{u^2+3} }du\]

\[u=\sqrt{3}tant~~~~du = \sqrt{3}\sec^2t dt\]

Finish it off

Answer 4

Thank you batman :D

Answer 5

Yw

Answer 6

can you guys help me now?

Answer 7

Once again Openstudy is saved!

Answer 8

@geerky42 can you help me