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Find the volume of solid formed by y=x^2 +1, x=0, x=2, rotated about x=2... i got 12pi cu. u.... but i am not really sure if my answer is correct...
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How did you get that? What was your integral?
\[2\pi \int\limits_{0}^{2} x(x^2 +1) dx\]
Looks to me like you are rotating about y = 0. What happened to x = 2?
Radius should be (2-x) Height should be (y-1)
Is this the region?|dw:1402108468090:dw| If yes, use @tkhunny's dimensions.
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