Question

Someone help, one question :<

http://oi57.tinypic.com/zl6hpl.jpg

Answer 1

What is the period of this sine function?

Answer 2

I can only assume 430, thats the only number given there

Answer 3

I have no idea how to do this =c

Answer 4

it is 430 because it repeats after 430

Answer 5

the formula to find the period T is

T = 2pi/B

solve for B to get

T = 2pi/B

BT = 2pi

B = 2pi/T

Answer 6

Then plug in the period of T = 430 to get

B = 2pi/T

B = 2pi/430

B = ???

Answer 7

.015 aprox?..

Answer 8

keep it as a fraction in terms of pi

Answer 9

860pi?

Answer 10

reduce 2pi/430

Answer 11

think of it as reducing 2/430 and then tack on pi at the end

Answer 12

sin215pi ?

Answer 13

2/430 doesn't reduce to 215

Answer 14

close though

Answer 15

It reduces to 1/215 doesnt it?

Answer 16

yeah you were thinking of 430/2 = 215

Answer 17

so that's why the answer is C

Answer 18

because we have this basic form

y = A*sin(Bx - C) + D

where B is used to determine the period T (T = 2pi/B)

Answer 19

Math is so confusing, but I think i get it x.x Thank you! Could you help with one more? I'll be posting it in a moment

Answer 20

ok go ahead