Question

ln(4x-2) = ln(8x)
I keep getting -1/2 but the answer is no solution, I dont get why?

Answer 1

whats in

Answer 2

\[\Large\rm 4x-2=8x\]Solving for x gives us,\[\Large\rm x=-\frac{1}{2}\]But you need to plug it back into the equation to make sure the solution works.

Answer 3

\[\Large\rm \ln(-4)\]Uh oh! :O

Answer 4

log of negative numbers is not defined in real domain.

Answer 5

oh ok thanks, i get it now

Answer 6

Good!

Answer 7

completely forgot about negative logs lol

Answer 8

No such thing as negative logs my friend.

Answer 9

there is, but in complex domain

Answer 10

I must study more advanced mathematics then