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Mathematics 17 Online
OpenStudy (anonymous):

@Hanishala Fan and Medal to calculate how cold it was this February so she started collecting the high temperatures each day. Use the Feb Calendar attached and your answer from question 2 to calculate the following information: What is the range? What is the median? What is the lower quartile? What is the upper quartile? How many days are in the interquartile?

OpenStudy (anonymous):

OpenStudy (anonymous):

can you arrange the values

OpenStudy (anonymous):

u want me to make them from least to greatest?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

arrange the data of february only and the range = greatest value - least value

OpenStudy (anonymous):

63,59,57,53,52,48,46,46,46,45,45,44,40,40,38,37,36,35,35,35,35,34,33,32,31,31,30,30,29,28,27,27,26,21,21

OpenStudy (anonymous):

you want it for FEBRUARY not for all so delete the values which belongs to JAn or MAR

OpenStudy (anonymous):

No dude that's all for Feburary

OpenStudy (anonymous):

26,27,27,,29,30,30,31,32,33,34,35,35,35,35,36,37,38,40,44,45,45,46,48,52,53,57,59,63

OpenStudy (anonymous):

so range =63-26 = 37

OpenStudy (anonymous):

No 63-21

OpenStudy (anonymous):

the median is the middle value but number of values is even =24 so median =(value(n/2)+value((n/2)+1))/2 =(35+36)/2= 35.5

OpenStudy (anonymous):

THERE are 35 numbers bro, not 24

OpenStudy (anonymous):

lower quartile =25 %of data first number of 50% of data will be even =14 so lower quartile is between number 7 ,8 lower quartile =(31+32)/2 =31.5 upper quartile = 75% of data the second number of data =14 so upper quartile is between number 21 ,22 upper quartile =(45+46)/2 =45.5

OpenStudy (anonymous):

inter quartile = upper quartile -lower quartile =45.5 -31.5 =14

OpenStudy (anonymous):

|dw:1402191566872:dw|

OpenStudy (anonymous):

the month of february is 28 day so number of data 28 you want to calculate every thing to february so you take values which belongs to february only

OpenStudy (anonymous):

@ so you will not take values in january or mars

OpenStudy (anonymous):

@Passionateboyy14

OpenStudy (anonymous):

and he told you in the question to use FEBRUARY calender

OpenStudy (anonymous):

the calendar is of febuary. THERE IS NO MARCH. its just written there. the calendar IS OF FEBUARY

OpenStudy (anonymous):

in the first row you have first 7 values in january in the last row you have one value in mars

OpenStudy (anonymous):

so (21,21,28,31,46,46,40) you will subtract them from your first arrange and get what i wrote

OpenStudy (anonymous):

but keep your mind with me february is 28 day how you got 35 ?

OpenStudy (anonymous):

well can u write it out for me. like this = range: mean :

OpenStudy (anonymous):

range =63 -26 =37 median =(35+36)/2=35.5 lower quartile = (31+32)/2= 31.5 upper quartile = (45+46)/2 =45.5 inter quartile = upper quartile -lower quartile =45.5 -31.5 = 14

OpenStudy (anonymous):

days in the inter quartile 14 day

OpenStudy (anonymous):

THANK YOU SOO MUCH

OpenStudy (anonymous):

u are welcome :)

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