Question

Medal


Solve sqrtx-1=x-3 check for extraneous solutions



A. No solution

B. x=5

C. x=2

D. x=2, 5

Answer 1

is it
\[\sqrt{x}-1=x-3\]
or
\[\sqrt{x-1}=x-3\]??

Answer 2

the second one

Answer 3

Square both sides. then you will get a quadratic equation. Solution to Q.E of the form is \[a^{2}+bx +c=0 \]
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 4

joseph91 is right

Answer 5

x-1=(x-3)^2
x-1=x^2-6x+9
\[x ^{2}-7x+10=0\]

Answer 6

solve this equation
there are two roots of this equation (2,5)
(x-2)(x-5)=0

Answer 7

quadratic equation should be
\[ax ^{2}+bx+c=0\]
joseph by mistaken wrote \[a ^{2}\]
instead of\[ax ^{2}\]

Answer 8

sorry for mistake