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Mathematics 11 Online
OpenStudy (anonymous):

|2x-3| > 5 ..is there any short method to solve this inequality within 1 minute?

OpenStudy (anonymous):

yes first you make two equations as 2x-3 > 5 2x+3 > 5 then solve for both equations and your done in less than a minute!

OpenStudy (anonymous):

check the equations that u wrote again

OpenStudy (anonymous):

I mean wouldn't it be 2x-3 > 5 and 2x-3>-5

OpenStudy (anonymous):

no i apologize i am wrong, the correct two equations are: 2x + 3 > 5 -(2x + 3) > 5 source: http://www.purplemath.com/modules/solveabs.htm

OpenStudy (anonymous):

awsomekrishn bro.,. ,, one of my teacher said in the very earlier that i can solve this inequality like this : as the inequality is |2x-3| > 5 so first i need to do like this: -3+2 = -1 and then i have to add it with the 5 and that means +5-1 = 4 so then i can get result like a pattern like : -1<x<4 okay?? ... but its not the result actually.... can you please describe the method if you guys know about it...

OpenStudy (anonymous):

Forget that method

OpenStudy (anonymous):

It is not straight forward

OpenStudy (anonymous):

Rule .1 Equation with one modulus sign ---> When you open the modulus , the number at the R.H.S , suppose it is 7 would become +7 and -7

OpenStudy (anonymous):

yes that's clear to me..and then i got two values with the equations ,,,, well thanks anyway ...it would be helpful if that short method would be in clear concept anyhow....

OpenStudy (anonymous):

That is a shortcut for doing fast calculations Well, are you from India , there is a reason i am asking this

OpenStudy (anonymous):

lol .... no ... I am from Bangladesh.... and can i know the reason? :p

OpenStudy (anonymous):

hmmm, you know hindi?

OpenStudy (anonymous):

yap kinda.,..,,, u from india? i guess ..

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

well so..... i can talk to u in hindi later ...if we are already became friends :p

OpenStudy (anonymous):

Yes why not

OpenStudy (anonymous):

Do you have some time to spare for watching some videos on modulus I aced my tet by watching this video , so i recommend it to you

OpenStudy (anonymous):

test*

OpenStudy (anonymous):

oh i appreciate that..... so can you forward me with one of the best vid link on youtube?

OpenStudy (anonymous):

https://www.youtube.com/watch?v=2j0jNjTGM3o This in hindi somewhat , has 22 parts

OpenStudy (anonymous):

well thanks again.... No.name... :)

OpenStudy (anonymous):

No problem

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