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Mathematics 8 Online
OpenStudy (anonymous):

How many combinations of 3 students can a teacher choose from 32 students? A. 96 B. 4960 C. 29,760 D. 32,768

OpenStudy (anonymous):

@aajugdar

OpenStudy (anonymous):

use combination formula

OpenStudy (anonymous):

wat is the formula

OpenStudy (anonymous):

ask google :3

OpenStudy (anonymous):

32C3 = 32! /29!3!

OpenStudy (anonymous):

which is 32*31*30 /3*2

OpenStudy (anonymous):

which is 4960

OpenStudy (anonymous):

is it in options? O.o

OpenStudy (anonymous):

yes so its B

OpenStudy (anonymous):

my internet is laggy so my posts arnt getting sent

OpenStudy (anonymous):

no hey r thanks

OpenStudy (anonymous):

welcome

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