OpenStudy (anonymous):

3cosx-2=0

OpenStudy (anonymous):

\[3\cos(x)-2=0\]\[3\cos(x)=2\]\[\cos(x)=\frac{2}{3}\]

OpenStudy (anonymous):

\[\cos^{-1}~~\frac{2}{3}\]\[Also,~3^2-2^2=9-4=5~~~~~~->~~~~~~~~~\sqrt{5}\]So the sides are\[~~2, ~~~~~~~~~~~~~~~~~~~~~~~~\sqrt{5},~~~~~~~~~~~~~~~~~~~~~~~~3\] adjacent opposite hypotenuse

OpenStudy (anonymous):

so therefore 3 cosx= 2 then cosx= 2/3) so arc cos or cos^-1 (2/3)= 48.1 degrees