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Trigonometry
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Find all solutions of the following equation. sin x cos x - 2 sin x = 0
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sin x cos x - 2 sin x = 0 factor out it, get sin x (cos x - 2) = 0 set up each factor be equal zero then solve for x sin x = 0 x = .... ? cosx - 2 = 0 cos x = 2 there is no solution for x
how did you get to sin x (cosx-2)? what happened to the -2 sin x?
He factorized it. For example,\[xy - 2y = y(x - 2)\]
okay, so if sin x = 0, wouldn't x be equal to 0pie and pie?
lol pi*
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