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f(x) = x+1/x+7 Find f^-1(-5)
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y = x+1/x+7 x/1 = y+1/y-3 x(y-3)=y+1 xy-3x=y+1 xy-y-3x=1 xy-y=3x+1 y(x-1)=3x+1 f^-1(x) = 3x+1/x-1 f^-1(5) = 3(-5)+1/-5-1=-15+1/-6=-16/-6=8/3
I didn't get the correct answer
@jim_thompson5910 @ganeshie8 @mathslover @jigglypuff314 @zzr0ck3r
y = x+1/x+7 x/1 = y+1/y-3 you changed the 7 to a 3?
oh I didn't see that!
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that will change my answer
I'm still trying so what I got was 17/3
x(y+7)=y+1 xy + 7x = y + 1 y - xy = 7x - 1 y (1-x) = 7x-1 y = (7x-1)/(1-x)
where did the +1 change to a -1?
@jigglypuff314
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you subtracted xy and -1 from both sides
OK, I see what you did :)
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