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Choose the factored form of the given equation. 6 x^2 + 2 x - 8 = 0 (6 x - 8)( x + 1) = 0 (6 x + 1)( x - 8) = 0 (6 x + 8)( x - 1) = 0
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in this case, you can expand each option, if you have a hard time factoring it.
You have to get the second term (when looking at ax²+bx+c) , ` bx` to have b=2 And the last term (the constant) c, to have c=-8. Which options gives that ?
(6 x - 8)( x + 1) = 0
?
do the slide and divide method
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