Question

The sum of two numbers is 70. The larger number is 4 more than twice the smaller number. What is the smaller number?

Answer 1

x + y = 70
x = 2y+4

Answer 2

smaller number = y
larger number = x
x + y = 70
x = 2y + 4
now sub in 2y + 4 in for x in the other equation
2y + 4 + y = 70
3y + 4 = 70
3y = 70 - 4
3y = 66
y = 22

x + y = 70
x + 22 = 70
x = 70 - 22
x = 48

check..
x = 2y + 4
48 = 2(22) + 4
48 = 44 + 4
48 = 48 (correct)

larger number (x) = 48
smaller number (y) = 22

Answer 3

Thanks.

Answer 4

anytime :)