Question

k^2 - 36/k^2 - 16 k + 60 ÷ k^2 - 12 k + 36/k^2 - 6k ⋅ 6k - 60/k^2 + 6k = ?

Answer 1

@Conqueror @SolomonZelman

Answer 2

I am not going to guess what the denominators and numerators are 500 times. Can you please re-write the question precisely?

Answer 3

\[\frac{ k^2 - 36 }{ k^2 - 16 k + 60 } \div \frac{ k^2 - 12 k + 6 }{ k^2 - 6 k } \times \frac{ 6 k - 60 }{ k^2 + 6 k } = ?\]

Answer 4

factorise numerators and denominators wherever possible, rest you can do i suppose, @greenhawk2000

Answer 5

no

Answer 6

I need help

Answer 7

Cannot factorize?
Hints:
\[a(a+b)=a^2+ab\]
\[a^2-b^2=(a+b)(a-b)\]
\[(a+b)^2=a^2+2ab+b^2\]
\[(a-b)^2=a^2-2ab+b^2\]