(sqrt 3x-2) +3=4x ?
Can someone help me with this question ?
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jhonyy9 (jhonyy9):
like a first add to the both sides minus 3 and in the second step square both sides to elimine the squarroot
ok ?
jhonyy9 (jhonyy9):
sqrt(3x-2) +3 = 4x
this is correct wrote ?
OpenStudy (anonymous):
yes
jhonyy9 (jhonyy9):
so can you calculi how i have wrote it above step by step ?
jhonyy9 (jhonyy9):
comen this is easy
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jhonyy9 (jhonyy9):
courage
jhonyy9 (jhonyy9):
than you add to the both sides minus 3 what will get ?
jhonyy9 (jhonyy9):
courage i will help you but you need to cooperate anything
jhonyy9 (jhonyy9):
sqrt(3x-2) +3 = 4x / + (-3)
sqrt(3x-2) +3 -3 = 4x -3
do you can continue it ?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
then you sqrt both sides by 2 ?
jhonyy9 (jhonyy9):
yes
jhonyy9 (jhonyy9):
you have got the result ?
OpenStudy (anonymous):
I got stuck after sqrting it by 2
jhonyy9 (jhonyy9):
why ? please write the calculi here
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OpenStudy (anonymous):
(sqrt3x-2)^2 = (4x-3)^2
3x-2 =4x-3 ?
jhonyy9 (jhonyy9):
the left side is right but the right side not is
you dont squared the (4x-3) ,why ?
OpenStudy (anonymous):
how do i do that?
jhonyy9 (jhonyy9):
(4x-3)^2 =(4x-3)(4x-3)
yes ?
OpenStudy (anonymous):
ohh okay i get it now
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jhonyy9 (jhonyy9):
can you get the right result now sure ?
OpenStudy (anonymous):
let me try hahah
OpenStudy (anonymous):
do i add the right side together ?
jhonyy9 (jhonyy9):
no there is (4x-3) time (4x-3)
OpenStudy (anonymous):
okay
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jhonyy9 (jhonyy9):
okay what ?
jhonyy9 (jhonyy9):
you dont like writing the calculi here ?
OpenStudy (anonymous):
3x-2=16x^2-6x+9
OpenStudy (anonymous):
is that correct ?
jhonyy9 (jhonyy9):
not is correct the right side
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OpenStudy (anonymous):
it's supposed to be 8x^2 ?
jhonyy9 (jhonyy9):
so (4x-3)*(4x-3)= 4x*4x -3*4x -3*4x +(-3)*(-3) = ?
jhonyy9 (jhonyy9):
do you see why your calculi not is right ?
jhonyy9 (jhonyy9):
so 4x*4x = 16x^2 is correct
so than continue
-3*4x =-12x and -3*4x=-12x so -12x -12x = -24x
yes ?
and (-3)*(-3) = +9
than now do you see where not is correct your calculi ?
OpenStudy (anonymous):
ohhhh I understand now
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jhonyy9 (jhonyy9):
than do you can finish it now easy ?
OpenStudy (anonymous):
0=16x^2-9x-7 ?
jhonyy9 (jhonyy9):
than
3x-2=16x^2 -24x +9
yes ?
jhonyy9 (jhonyy9):
how you get -9x and -7 ?
OpenStudy (anonymous):
16x^2 - 24x + 9 -3x-2
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jhonyy9 (jhonyy9):
why -2 ?
OpenStudy (anonymous):
so the other side can equal to 0
jhonyy9 (jhonyy9):
but the -2 not is right
jhonyy9 (jhonyy9):
because on the left side there are 3x-2 so than thiis on the right side will be -3x+2
yes ?
OpenStudy (anonymous):
ahhhh okay
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OpenStudy (anonymous):
so instead of 7 it will be 11 ?
jhonyy9 (jhonyy9):
yes and the term of x how will be ?
jhonyy9 (jhonyy9):
first please write it correct the quadratic what you need to get
jhonyy9 (jhonyy9):
so 16x^2 and how you continue it ?
OpenStudy (anonymous):
I don't know haha
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jhonyy9 (jhonyy9):
so there are -24x-3x
yes ?
OpenStudy (anonymous):
yes
jhonyy9 (jhonyy9):
than how will be the resulted quadratic correct ?
jhonyy9 (jhonyy9):
you dont like continue it ?
OpenStudy (anonymous):
sorry I was going over my problem
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OpenStudy (anonymous):
0=16^2-21x+11
jhonyy9 (jhonyy9):
ok so than how will be ?
jhonyy9 (jhonyy9):
there are -24x-3x
OpenStudy (anonymous):
which is 21x
jhonyy9 (jhonyy9):
-24-3 why is it 21 ?
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OpenStudy (anonymous):
ohh sorry it's 27 right ? because of the - sign
OpenStudy (anonymous):
I'm sorry I'm stupid in math.
jhonyy9 (jhonyy9):
so than how will be the quadratic correct ? and you need to solve it ?
OpenStudy (anonymous):
(4x-3)(x-1)
jhonyy9 (jhonyy9):
no begin it with 16x^2
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OpenStudy (anonymous):
16x^2 -27x+11 is this what your talking about ?
jhonyy9 (jhonyy9):
yes
than this quadratic you need to solve it ,yes ?
OpenStudy (anonymous):
that would be the answer ?
jhonyy9 (jhonyy9):
i dont know
do you know how to yolve a quadratic ?
OpenStudy (anonymous):
Yes
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jhonyy9 (jhonyy9):
so than you need to solve it
how ?
i think you need to us the discriminant method
jhonyy9 (jhonyy9):
because you not can factoriz it ,yes ?
jhonyy9 (jhonyy9):
yes this is right but in case of your exercise how will be
first you need to calculi the roots of quadratic
OpenStudy (anonymous):
I don't know ?
jhonyy9 (jhonyy9):
us the discriminant method
do you know it ?
D=b^2 -4ac
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jhonyy9 (jhonyy9):
and x1,2 = ?
OpenStudy (anonymous):
No I haven't learn it
jhonyy9 (jhonyy9):
so than i think that you dont write correct your exersice above
how is it in your book ?
OpenStudy (anonymous):
I checked it's correct
OpenStudy (anonymous):
I was saying that I haven't learned about the discriminant method
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jhonyy9 (jhonyy9):
but this qudratic you can solve it using this method
OpenStudy (anonymous):
ohh but I don't know how to use that method.
jhonyy9 (jhonyy9):
sorry but than i think that you need to learn it for you can solve this exersice