Question

Simplify this expression: sec(–α) cosα/cotα

sinα

−sinα

tanα

−tan

Answer 1

\[\huge \frac{\sec(–α) \cosα}{\cotα}\]
\[\huge \rightarrow \frac{\secα \times \cosα}{\cotα}=\frac{1}{\cotα}=\tanα \]

Reason: sec(–α) = sec α

sec α * cos α =1

Answer 2

Hence, third option is correct answer..