Question

Determine the equation(s) of the vertical asymptote(s) of the function y=0.9^x/2x^2-3 plz help!

Answer 1

set the denominator equal to zero,
solve fo r\(x\)

Answer 2

\[2x^2-3=0\\
2x^2=3\\
x^2=\frac{3}{2}\\
x=\pm\sqrt{\frac{3}{2}}\]
everything but that