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g(x) = 3-sqrt(x) g^-1(x) = ?
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solve \[x=3-\sqrt{y}\] for \(y\)
1) subtract 3 2) change the sign 3) square both sides
thanks!
yw
help with 1 more ?
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sure
let g(x) = ax + b..... g(x+h) -g(x) / h
\[g(x)=ax+b\\ g(x+h)=a(x+h)+b=ax+ah+b\\ g(x+h)-g(x)=ax+ah+b-(ax+b)=ah\]
divide by \(h\) and you get the slope , \(a\)
thank you last 1, if f(x) = x^2 -1 then f(x+h) - f(x) / 2
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