Question

A force of 4 N acts on a body of mass 2 kg for 4 s. Assuming that the body to be initially at rest find : A) its velocity when force stops acting on it. B) The distance covered in 10 s after force starts acting on it

Answer 1

Did you solve it?

Answer 2

F*t =m(v-u)
4 * 4 = 2 (v-0)
16 = 2v
v = 8

b) F = m x a
4 = 2a
a=2
s= ut plus a/2at^2
s = 0 plus 1/2 x 2 x 10^2
s= 100