Question

Integrate using a trig sub:

Answer 1

\[\LARGE \frac{x^3}{\sqrt{1-x^2}}~dx\]

Answer 2

use trig sub :)

Answer 3

oh, and parts.

Answer 4

I just noticed I forgot my integral.. I must be tired

\[\LARGE \int \frac{x^3}{\sqrt{1-x^2}}~dx\]
The \(\Large \int \frac{1}{\sqrt{1-x^2}}dx=sin^{-1}x\)?

Answer 5

I forgot all my math, but I think that is correct.

Answer 6

sub
\(x=\sin \theta\)
\(dx= \cos \theta d\theta\)

\(\large \int \frac {(\sin \theta)^3 \cos \theta d\theta }{ \sqrt {1-\sin^2 \theta }}\)
\(\large \int \frac {(\sin \theta)^3 \cos \theta d\theta }{ \cos \theta }\)

\(\large \int (\sin \theta)^3 d \theta \)