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Mathematics 17 Online
OpenStudy (anonymous):

√3x + 10 = x + 4

OpenStudy (conqueror):

You must like green checkmarks @SolomonZelman

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm \sqrt{3x+10}=x+4 }\) Like this ?

OpenStudy (anonymous):

the square root is only for the 3x

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm \sqrt{3x}+10=x+4 }\)

OpenStudy (anonymous):

yes

rishavraj (rishavraj):

answer is -8.2??

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm \sqrt{3x}+10=x+4 }\) \(\large\color{red}{ \rm ~~~~~~~-10~~~~~~~-10 }\) \(\large\color{midnightblue}{ \rm \sqrt{3x}=x-6 }\) \(\large\color{midnightblue}{ \rm 3x=x^2-12x+36 }\)

OpenStudy (anonymous):

fuk yha carnifex!!! haha

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm 3x~~~=x^2-12x+36 }\) \(\large\color{red}{ \rm -3x~~~~~~~~~~-3x }\) \(\large\color{midnightblue}{ \rm 0=x^2-9x+36 }\) \(\large\color{midnightblue}{ \rm x^2-9x+36 =0 }\)

OpenStudy (anonymous):

shouldn't it be -15x ?

OpenStudy (solomonzelman):

yes, my bad

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm x^2-15x+36 =0 }\)

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm x^2-15x+36 =0 }\) \(\large\color{midnightblue}{ \rm (x-3)(x-12)=0 }\)

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm x=? }\)

OpenStudy (anonymous):

x = 12

OpenStudy (anonymous):

thank you

OpenStudy (solomonzelman):

yes x=12, and x=3

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