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Mathematics
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OpenStudy (anonymous):
√3x + 10 = x + 4
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OpenStudy (conqueror):
You must like green checkmarks @SolomonZelman
OpenStudy (solomonzelman):
\(\large\color{midnightblue}{ \rm \sqrt{3x+10}=x+4 }\) Like this ?
OpenStudy (anonymous):
the square root is only for the 3x
OpenStudy (solomonzelman):
\(\large\color{midnightblue}{ \rm \sqrt{3x}+10=x+4 }\)
OpenStudy (anonymous):
yes
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rishavraj (rishavraj):
answer is -8.2??
OpenStudy (solomonzelman):
\(\large\color{midnightblue}{ \rm \sqrt{3x}+10=x+4 }\)
\(\large\color{red}{ \rm ~~~~~~~-10~~~~~~~-10 }\)
\(\large\color{midnightblue}{ \rm \sqrt{3x}=x-6 }\)
\(\large\color{midnightblue}{ \rm 3x=x^2-12x+36 }\)
OpenStudy (anonymous):
fuk yha carnifex!!! haha
OpenStudy (solomonzelman):
\(\large\color{midnightblue}{ \rm 3x~~~=x^2-12x+36 }\)
\(\large\color{red}{ \rm -3x~~~~~~~~~~-3x }\)
\(\large\color{midnightblue}{ \rm 0=x^2-9x+36 }\)
\(\large\color{midnightblue}{ \rm x^2-9x+36 =0 }\)
OpenStudy (anonymous):
shouldn't it be -15x ?
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OpenStudy (solomonzelman):
yes, my bad
OpenStudy (solomonzelman):
\(\large\color{midnightblue}{ \rm x^2-15x+36 =0 }\)
OpenStudy (solomonzelman):
\(\large\color{midnightblue}{ \rm x^2-15x+36 =0 }\)
\(\large\color{midnightblue}{ \rm (x-3)(x-12)=0 }\)
OpenStudy (solomonzelman):
\(\large\color{midnightblue}{ \rm x=? }\)
OpenStudy (anonymous):
x = 12
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OpenStudy (anonymous):
thank you
OpenStudy (solomonzelman):
yes x=12, and x=3
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