Question

Need some Algebra 2 help!

Answer 1

what u need help with sexy

Answer 2

im doing Alg 2-2 right now too

Answer 3

Find the solution to the equations.

2x - y = -3
x + y = 0

Answer 4

Input in standard form the equation of the given line.

The line that passes through (1, 5) and (-2, 3)

Answer 5

2x-3y+13=0

Answer 6

it is 3y-2x-13=0

Answer 7

Input in standard form the equation of the given line.

The line that passes through (-1, -3) and (2, 1)

Answer 8

(1 - (-3) / (2 - (-1)
(1 + 3) / (2 + 1)
4/3 is your slope

y = mx + b
(2,1)..x = 2 and y = 1
slope(m) = 4/3
now we sub
1 = 4/3(2) + b
1 = 8/3 + b
1 - 8/3 = b
3/3 - 8/3 = b
- 5/3 = b

y = 4/3x - 5/3 -- multiply by 3
3y = 4x - 5
-4x + 3y = -5
4x - 3y = 5
4x - 3y - 5 = 0

Answer 9

balls

Answer 10

what brought that on ?

Answer 11

ball is life

Answer 12

I dont think those are right

Answer 13

the last one!