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whats the slope of your line?
i don't know how to find that..:/
the change in g(x) as x changes by 1, or formulaically:\[\frac{g(0)-g(-1)}{0-(-1)}\]
−1 −9.2 0 −9 ^^^ logically it changes by .2
notice that if we start at x=0, y=-9 we are below the circle, and we dont ever reach a higher lever for 5 values of x|dw:1402415198199:dw|
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do u have to plot any points on the circle graph?
you can if you want to .... then draw a liine between the points to see if they will intersect the circle.
yeah, the last one :)
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