Question

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Answer 1

what is the circumference of a circle with that radius?

Answer 2

2pi r?

Answer 3

actually yes ... and we want a ratio of pi/3 out of 2pi of that circles properites soo

\[\frac{pi/3}{2pi}2pi~r\]
\[r~pi/3 \]

Answer 4

Ok, what is the next step? These are my options:

10 pi over 3cm

16 pi over 3cm

pi over 3cm

5 pi over 3cm

Answer 5

they give you r ... and you have pi/3 :/ multiply them together and simplify as needed.