Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = -6. Lol you should help me.

Question

campbell_st · Answer

ok... 

so I use the form 

$$(x - h)^2 = 4a(y - k)$$

to start a question of this type... 

the vertex is (h, k)

The distance from the vertex to the focus is a

which is also the distance from the vertex to the directrix. 

then the distance from the focus to the directrix is 2a

|dw:1402429771204:dw|

the vertex is on the line of symmetry midway between the focus and directrix. 

hope it helps