how many real number solutions does the equation have?
\[y=5x ^{2}+8x-7\]
@iambatman um no test. i don't cheat. it's for practice.
For ax^2 + bx + c Find the discriminant, b^2 - 4ac
If b^2 - 4ac > 0 then there is 2 real solutions If b^2 - 4ac = 0 then there is 1 real solution If b^2 - 4ac < 0 then there is no real solutions
'is' should be 'are' in the first and last line, but I ain't no dang grammar teacher
@agent0smith LOL but I don't get it?
For ax^2 + bx + c Find the discriminant, b^2 - 4ac You have 5x^2 + 8x − 7
@agent0smith so it would be 8^2-4(5)(-7) ??
since the y-intercept is (0,-7) which means below the x-axis, and the parabola opens up, there are two real solutions. No need to use discriminant
^true
@sourwing okay so there would be 2 solutions?
yea
8^2-4(5)(-7) = a positive number, which also from above tells you two solutions, from If b^2 - 4ac > 0 then there is 2 real solutions If b^2 - 4ac = 0 then there is 1 real solution If b^2 - 4ac < 0 then there is no real solutions
@sourwing okay thank u <3
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