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OpenStudy (anonymous):
lim sin²x/5x x-->0 Ok, so the answer is zero but can someone show me and explain to me why it is zero?? I am not sure how to start working out the solution and how to get that answer. Any help will do! Please and thank you!
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OpenStudy (anonymous):
use the fact that lim (sinx)/x = 1 x->0
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