Question

Can someone explain how to solve this equation :D

3k(2k+8)(3k-9)=0

A. 4,0,3.
B. -9,-3.
C. 3,-3.
D. -4,0,3.
E. 3.

Answer 1

now u have factorised all terms.. now just put 3k = 0, (2k+8) = 0 and so on

Answer 2

@robtobey and @rishavraj I need the steps

Answer 3

so i will know how to solve it

Answer 4

3k=0, k=0
2k+8=0, k=-4
3k-9=0, k=3

Answer 5

ok

Answer 6

thanks you guys :D