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OpenStudy (anonymous):
Vectors problem: Let ABCD be a parallelogram and a point P such that BP = 2PD. Prove that: BP = 2/3 (BA + BC)
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ganeshie8 (ganeshie8):
|dw:1402477866499:dw|
ganeshie8 (ganeshie8):
Are you given any diagram ? where should I put the point P ? on the diagonal BD ?
OpenStudy (anonymous):
That's all problem( no diagram no nothing)
OpenStudy (anonymous):
|dw:1402478118888:dw| That's my best guess but I'm not sure
OpenStudy (anonymous):
Are we assuming point p is in the interior of the parallelogram or what?
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