Question

Which expression is equivalent to sec2xcot2x?

sin2x

csc2x

1/cos2x

1/sin2x

Answer 1

\(\large\color{blue}{ \rm sec^2x~cot^2x }\) Like this ?

Answer 2

yes

Answer 3

` sec²x = 1 / cos²x ` and ` cot²x = cos²x / sin²x `

Re-write the expressions in terms of sines and cosines.

1) Then cancel out the `cos²x` on top and bottom
2) and apply ` 1/ sin²x = csc²x `

Answer 4

Thank you

Answer 5

Anytime, if you need more help, let me know.