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integrate ((0.25+(x^2))^0.5)
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substitute u for (0.25+x^2)
but i try it . it will be more complex
we have formula for this, why don't you apply? \[\int{\sqrt{u^2\pm a^2}}du = \dfrac{u}{2}\sqrt{u^2\pm a^2}\pm\dfrac{a^2}{2}ln|u+\sqrt{u^2\pm a^2}|\] you case is + only, and u ^2 = 0.5^2 = 0.25 Dat sit
thank you
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