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OpenStudy (anonymous):
what is 8x-16 factored
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OpenStudy (anonymous):
8(x - 2)
OpenStudy (anonymous):
Notice that each term has a multiple of 8, so you can factor out an 8 from each term. \[8x-16=>8(x-2)\]
OpenStudy (anonymous):
oh okay! thank you!
OpenStudy (anonymous):
what is (x^2-4/x-3)(x+2/8x-16)
OpenStudy (anonymous):
how do I condense 6(ln3+lnx)+1/4ln3
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