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OpenStudy (awkwardpanda):
What is S_10 for 1+2+4+8+... a.256 b.511 c.1023 d.2047
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OpenStudy (anonymous):
\[1+2+4+8+16+32+64+128+256+512\]
OpenStudy (awkwardpanda):
I so knew that.
OpenStudy (anonymous):
or if you prefer, \[2^{10}-1\]
OpenStudy (anonymous):
since \(2^9=512\) (the last number) then \(2^{10}=1024\) so \(2^{10}-1=1023\)
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