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Mathematics 7 Online
OpenStudy (awkwardpanda):

What is S_10 for 1+2+4+8+... a.256 b.511 c.1023 d.2047

OpenStudy (anonymous):

\[1+2+4+8+16+32+64+128+256+512\]

OpenStudy (awkwardpanda):

I so knew that.

OpenStudy (anonymous):

or if you prefer, \[2^{10}-1\]

OpenStudy (anonymous):

since \(2^9=512\) (the last number) then \(2^{10}=1024\) so \(2^{10}-1=1023\)

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