Question

simply tan^2x/secx
Please someone answer...asap with all steps

Answer 1

\[\tan^2(x)/\sec(x)\]
\[=\frac{ \sin^2(x) }{ \cos^2(x) } * \frac{ 1 }{ \cos(x) }\]
this simplifies down to \[= \frac{ \sin^2(x) }{ \cos(x) } = \sin(x) *\tan (x) = \sec(x)-\cos(x)\]