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Quotient of 4 + 6i/ 2 - 3i a.-5/26 - 6/13i b. - 10/13 + 24/13i c. 2 -2i d. None
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\[\frac{4+6i}{2-3i}\cdot\frac{2+3i}{2+3i}=\frac{8+12i+12i+18i^2}{4-9i^2}=\frac{8-18+24i}{4+9}=\frac{-10+24i}{13}\]
so B?
yes
Thank you so much. I did this on my calculator and chose D. Your explanation helps.
yw
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