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Mathematics 14 Online
OpenStudy (anonymous):

Factor 8x^3 - 125

OpenStudy (sweetburger):

|dw:1402555756946:dw| how should we reduce this from here?

OpenStudy (anonymous):

(2x + 5) (4x^2+10x-25)?

OpenStudy (sweetburger):

u wot m8?

OpenStudy (sweetburger):

you never finished the other question

OpenStudy (anonymous):

Well is this one right?

OpenStudy (sweetburger):

that is not how you simplify 8x^3=125

OpenStudy (anonymous):

I mean factor.

OpenStudy (anonymous):

So then am I right?

OpenStudy (sweetburger):

your correct except for the fact that it should be (2x+5)(4x^2+10x-25)

OpenStudy (anonymous):

Thanks.

OpenStudy (anonymous):

\[\Huge 8x^3 - 125 = (2x)^3 - (5)^3\] \[= (2x - 5)[(2x)^2+2x \times 5 + (5)^2]\] \[\huge = (2x - 5)[4x^2+10x + 25]\] is the required factor. Formula used: \[\huge (a^3 - b^3) = (a - b) (a^2 + ab + b^2) \]

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