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Given: ACIIBD and ABIICD
Proven:

Question

Need help with this urgently. 

Given: ACIIBD and ABIICD 
 Proven: <PCQ is complementary to <ABC 

 Proof: ACICD m<OCQ= 90 degrees by the definition of perpendicular lines. By angle addition, we can say m<OCQ= m<OCP + m<PCQ. But since m<OCQ= 90 degrees, m< OCP=90 degrees, m<OCP+m<PCQ= 90 degrees by the Transitive Property of Equality. 

 (Missing Step) 

 By the definition of congruent angles, m<OCP=m<ABC. This leads to m<ABC+m<PCQ=90 degrees by the Transitive Property of Equality. So, based on the definition of complementary angles, <PCQ is complementary to <ABC.

aldana.navea · Answer

answers: 

 a. PCQ and ACP are supplementary by the Linear Pair Theorem. 
 b. For parallel lines cut by a transversal, corresponding angles are congruent, so ACB PCQ. 
 c. OCP BCD by the Vertical Angles Theorem 
 d.For parallel lines cut by a transversal, corresponding angles are congruent, so OCP ABC. 
 e.For parallel lines cut by a transversal, corresponding angles are congruent, so OCA CBD.

aldana.navea · Answer

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