Question

A container has 50 electronic components, of which 10 are defective.
If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

Answer 1

P(defect) * P(defect) * P(defect) * (number of ways to choose 3 from 8)

Answer 2

forgot to include the 5 non defects

try the binomial distribution, if the replacement factor is getting in the way then try the hypergeometric