2log(x+3)+3log(x-7)-5log(x-2)-log(x^2) what is another way i can write this --- i have an idea but i dont know if i am right or wrong

Question

anonymous · Answer

$$ \frac{ (x+3)^{2} (x-7)^{3} }{ (x-2)^{5} x ^{^{2}} }$$

anonymous · Answer

wow that took forever to write that is what i would assume would be it

amistre64 · Answer

$$y=2log(x+3)+3log(x-7)-5log(x-2)-log(x^2)$$
$$e^y=e^{2log(x+3)+3log(x-7)-5log(x-2)-log(x^2)}$$
$$\large e^y=e^{2log(x+3)}e^{3log(x-7)}e^{-5log(x-2)}e^{-log(x^2)}$$
$$\large e^y=\frac{(x+3)^2(x-7)^3}{(x-2)^5(x^2)}$$
$$y=log\left[\frac{(x+3)^2(x-7)^3}{(x-2)^5(x^2)}\right]$$

amistre64 · Answer

you did fine, but you missed the log

anonymous · Answer

ohhhhh ok n_n yay close ... i just need one thing soo close hahah thank you ! @amistre64

amistre64 · Answer

youre welcome