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Please help me!!!! Will give medal :)
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Evaluate 27 × a^-2 for a = 3. A)\[\frac{ 1 }{ 3 }\] B)\[\frac{ 1 }{ 9 }\] C) 9 D) 3
This is the only question I need help with!!! Please help!!!
do u remember a^-1 = 1/a ???
Sure.... Yes....
so just apply same steps....
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So 1/3 ?
@rishavraj
what 1/3
I think that's the answer..... Am I right?
no u aint...just solve it again...u will surely be able
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Uhhh, can u explain more please :)
a^-1 = 1/a likewise a^-2 = 1/a^2
3^2= 9.... So 1/9
yup..now multiply.....
multiply? 0.o
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27*1/9
3?
yup...u r correct...
Thanks!!!!!
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