Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force of 5.2 N is applied.
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q=?
So the formula would go E=5.2/7*10^5 right?
no
there r charge here
thete r 2 charge here
Oh dear, so what I'm gathering is that I need to find the value of q first, and then I have to put that into the equation.
need some discussion with u first
Okay.
i think ur given charge is for which electric field produced. right?
I believe so yes
E=F/q here q is test charge nd its not given
Okay, that's what I thought.
do u wanna c ur question once again , if any data missing?
I copied it over directly, all the info is there.
if distance between test charge nd a charge is given, then its possible to find out electric field
okay I'll have to message my teacher.
ok
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