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Physics 16 Online
OpenStudy (anonymous):

Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force of 5.2 N is applied.

OpenStudy (isaiah.feynman):

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OpenStudy (shamim):

q=?

OpenStudy (anonymous):

So the formula would go E=5.2/7*10^5 right?

OpenStudy (shamim):

no

OpenStudy (shamim):

there r charge here

OpenStudy (shamim):

thete r 2 charge here

OpenStudy (anonymous):

Oh dear, so what I'm gathering is that I need to find the value of q first, and then I have to put that into the equation.

OpenStudy (shamim):

need some discussion with u first

OpenStudy (anonymous):

Okay.

OpenStudy (shamim):

i think ur given charge is for which electric field produced. right?

OpenStudy (anonymous):

I believe so yes

OpenStudy (shamim):

E=F/q here q is test charge nd its not given

OpenStudy (anonymous):

Okay, that's what I thought.

OpenStudy (shamim):

do u wanna c ur question once again , if any data missing?

OpenStudy (anonymous):

I copied it over directly, all the info is there.

OpenStudy (shamim):

if distance between test charge nd a charge is given, then its possible to find out electric field

OpenStudy (anonymous):

okay I'll have to message my teacher.

OpenStudy (shamim):

ok

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