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If P(A) = 0.3 and P(B)=0.4 and P(A∩B) = 0.12, are A and B independent?
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If it were independent then \[ \Pr(A\cap B) = \Pr(A)\times \Pr(B) \]
Plug in the values and see if this equation holds.
If P(AυB) = 0.7, what is P(A∩B)? i got 0
What? They didn't give you \(\Pr(A\cup B)\).
oh its 0.7
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i got 0 as the answer, is it right
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