Question

Multiply out and simplify to obtain a sum of product:
(A+B)(C+B)(D'+B)(ACD'+E)

Answer 1

Boolean algebra

Answer 2

(A+B)(C+B)(D'+B)(ACD'+E)
=(AC+AB+BC+B)(D'+B)(ACD'+E)
=(AC+B)(D'+B)(ACD'+E) [AB+BC+B=AB+B(C+1)=AB+B=B(A+1)=B]
=(ACD'+ACB+BD'+B)(ACD'+E)
=(ACD'+B)(ACD'+E) [ACB+BD'+B=ACB+B(D'+1)=ACB+B=B(AC+1)=B]
=ACD'+ACD'E+ACD'B+BE
=ACD'+BE